How to apply the projection of sunlight to the spherical earth in miniature and compare the results with reality.

Rays of the sun and the angle of its fall on Earth and the application of the Triangle law. It will simply prove to us the distance between the sun and the Earth and this will be published independently later. 

What matters to us here are the ways in which miniature models are created in communication sites and on YouTube through rough images or through a computer program. 

I think it's one of the right ways to make a mini-experiment, taking the numbers and dividing them by a fixed number, so that the model can be relatively close to reality (taking into account the external influences and the consequences involved in changing the results during the work if any). 

In the practical experience of applying the shape of sunlight and its access to the Earth, you have to take the measurements adopted by NASA as the strongest reference for information, science and discoveries and the Earth's spherical (and beyond) to ensure that your results are as follows: Earth diameter 12742 kg and sun diameter 1391400 Kilo and the distance between the Earth and the sun 149.6 million kilo to bring these dimensions to experience realistic process we assume now the earth diameter equals 1 mm 12742 = 1 and so we divide the diameter of the sun on earth diameter 1391400 ÷ 12742 = 109.91 mm as well as dividing the distance between the Earth and the sun on earth diameter 149.6 million ÷ 12742 equals 11740.7 mm, where the sizes are minimized with the distances, the earth is a circle with a single diameter and the Sun Circle is 109 ml and the distance between them is 11.74 meters.

And you can imagine you could reach the sunlight as the attached image if these dimensions and sizes are actually real as NASA says???!!!!!

Or the law of the triangle is closer to right as the sun reaches the earth.